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4.9x^2-6x-275=0
a = 4.9; b = -6; c = -275;
Δ = b2-4ac
Δ = -62-4·4.9·(-275)
Δ = 5426
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{5426}}{2*4.9}=\frac{6-\sqrt{5426}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{5426}}{2*4.9}=\frac{6+\sqrt{5426}}{9.8} $
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